12c^2+19c-21=0

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Solution for 12c^2+19c-21=0 equation:


Simplifying
12c2 + 19c + -21 = 0

Reorder the terms:
-21 + 19c + 12c2 = 0

Solving
-21 + 19c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-7 + -3c)(3 + -4c) = 0

Subproblem 1

Set the factor '(-7 + -3c)' equal to zero and attempt to solve: Simplifying -7 + -3c = 0 Solving -7 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -3c = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -3c = 0 + 7 -3c = 0 + 7 Combine like terms: 0 + 7 = 7 -3c = 7 Divide each side by '-3'. c = -2.333333333 Simplifying c = -2.333333333

Subproblem 2

Set the factor '(3 + -4c)' equal to zero and attempt to solve: Simplifying 3 + -4c = 0 Solving 3 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -4c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -4c = 0 + -3 -4c = 0 + -3 Combine like terms: 0 + -3 = -3 -4c = -3 Divide each side by '-4'. c = 0.75 Simplifying c = 0.75

Solution

c = {-2.333333333, 0.75}

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